Authors: Colin James III
For all p, p+p=p (1.1). #p>((p+p)=p) ; TTTT TTTT TTTT TTTT (1.2). For one p, p+p=p (2.1). %p>((p+p)=p) ; TTTT TTTT TTTT TTTT (2.2). Axiom of associativity (3.1). ((p+q)+r)=(p+(q+r)) ; TTTT TTTT TTTT TTTT (3.2).
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[v1] 2018-07-25 18:48:36
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