Authors: Raji Heyrovska
During the synthesis of a deuteron nucleus from a neutron and a proton, an electron, positron pair and an antineutrino, neutrino pair are released. The electrostatic energy (order of MeV) of the former pair is released as gamma radiation and is equivalent to the mass defect. Based on the largest mass defect per nucleon (MDPN) as the criterion of nuclear stability, it. is estimated that, in general, for a nuclide X(Z,N) with a fractional mass defect f , the MDPN(nu) due to neutrinos/antineutrinos alone is equal to fk(n) (Z/(z+N)), where the proportionality constant k(n) = 0.7 micro atomic mass unit. Since f is of the order of 0.01, MDPN(nu) is in nano-atomic mass units, which is the right order of the mass of neutrinos. (This paper is reprinted with permission from Desktop publication (1998) by Arjun consultancy & publishing Inc.,Wayne N.J.(USA))
Comments: 13 pages. Text: pp 1-7; pages 8-13 (please ignore the handwritten numbers): Table 1, legends for Figs. and 3 Figures; Paper presented at 216th National Meeting of the American Chemical Society, Boston, Aug. 1998, short abstract no. 9.
[v1] 2017-11-23 12:30:02
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