Authors: Hugh Wang
If we refer to a string for Turing machines as a guess and a rejectable substring a flaw, then all algorithms reject similarly flawed guesses flaw by flaw until they chance on an unflawed guess, settle with a flawed guess, or return the unflawed guesses. Deterministic algorithms therefore must identify all flaws before guessing flawlessly in the worst case. Time complexity is then bounded below by the order of the product of the least number of flaws to cover all flawed guesses and the least time to identify a flaw. Since there exists 3-SAT problems with an exponential number of flaws, 3-SAT is not in P, and therefore P!=NP.
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