Authors: Gerges Tawdrous
Mercury data provides us with many unsolved puzzles… let's take a look at some of them in following: -Mercury orbital Circumference = 360 million km ….. i.e. 1 million km for each 1 degree. - Mercury Ceres distance = 360 million km also… i.e. Mercury during his orbital period moves a distance = Mercury Ceres distance -Mercury Jupiter distance = 720.7 million km…. i.e. Mercury during 2 orbital periods moves a distance = Mercury Jupiter distance! Not only that -Mercury day = 2 Mercury orbital periods approximately (just minus 84 minutes)… that means, Mercury during his day period moves a distance = Mercury Jupiter distance.. In fact there are more puzzles in Mercury data, let's see that in following: -Mercury day 4222.6 hours = 3 x Mercury rotation period 1407.6 hours (no error) -Venus rotation period 5832.5 hours = Mercury rotation period 1407.6 x (Π+1) But -Mercury orbital distance = 57.9 mkm if we use this value to find the ordinary orbital circumference by the equation 2ΠR we'll reach to 364 million km, that means Mercury Velocity daily = (Π+1) x 1 million km that means 88 days (Mercury orbital period) x (Π+1) x 1 million km = 364 million km = 2ΠR where R =57.9 million km Please remember -Mercury actual velocity = 47.4 km/ second which means Mercury orbital circumference = 360 million km, means 1 million km for each 1 degree… The current theories tell us easily, all previous data are found by Pure coincidences and there are no geometrical or physical reasons behind And I claim that, Because the solar group is one machine, each planet is one gear in this same machine, for that reason the previous data are created depending one each other… To see the picture as clear as possible, we should answer the basic question which is Why Mercury moves during his day a distance = mercury Jupiter distance? Let's try to answer this question in this paper
Comments: 8 Pages.
[v1] 2018-08-20 19:11:28
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