## Fermat's Last Theorem. Proof of P. Fermat? (In Russian)

**Authors:** Victor Sorokine

Contradiction: Any prime factor r of the number R in the equality A n =A n +B n [...=(A+B)R]
has a single ending 0...01 of infinite length; where r≠n.
All calculations are done with numbers in base n, a prime number greater than 2.
Противоречие: В равенстве A n =A n +B n [...=(A+B)R] любой простой сомножитель r (r≠n,
простое n>2) числа R имеет (в базе n) единичное окончание 0...01 бесконечной длины.
Все вычисления проводятся в системе счисления с простым основанием n>2.

**Comments:** 2 Pages. Russian version

**Download:** **PDF**

### Submission history

[v1] 2018-04-02 12:50:23

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