Authors: Marius Coman
In a previous paper I presented seven sequences of numbers of the form 2*k*P – (30 + 290*n)*k – 315, where P is Poulet number, and I conjectured that two of them have all the terms odd abundant numbers and the other five have an infinity of terms odd abundant numbers. Because it is known that all the smaller numbers of amicable pairs are abundant numbers (see A002025 in OEIS), in this paper I revert the relation from above and I conjecture that all Poulet numbers P divisible by 5 can be written as P = (A + 315 + (30 + 290*n)*k)/(2*k), where A is a smaller of an amicable pair and n and k naturals. For example: 645 = (12285 + 315 + 30*10)/(2*10); also 1105 = (12285 + 315 + 2060*84)/(2*84) or 1105 = (69615 + 315 + 320*37)/(2*37). Note that for the first 17 such Poulet numbers there exist at least a combination [n, k] for A = 12285, the first smaller of an amicable pair divisible by 5!
Comments: 3 Pages.
[v1] 2018-01-24 11:27:10
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